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8k^2-9k-7=0
a = 8; b = -9; c = -7;
Δ = b2-4ac
Δ = -92-4·8·(-7)
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{305}}{2*8}=\frac{9-\sqrt{305}}{16} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{305}}{2*8}=\frac{9+\sqrt{305}}{16} $
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